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TOPO如下~
这是一个帧中继网络,没有使用子接口
物理接口全部关闭了水平分割,运行了EIGRP协议~
RF1为帧中继交换机,配置如图~
R1 R2 R3接口配置如下~
R1配置~
!
interface Loopback0
ip address 1.1.1.1 255.255.255.0
!
interface Serial0/0
ip address 123.1.1.1 255.255.255.0
encapsulation frame-relay
serial restart-delay 0
frame-relay map ip 123.1.1.3 103 broadcast
frame-relay map ip 123.1.1.1 102 broadcast
frame-relay map ip 123.1.1.2 102 broadcast
no frame-relay inverse-arp
!
!
router eigrp 100
network 1.1.1.0 0.0.0.255
network 123.1.1.0 0.0.0.255
auto-summary
!
R2配置~
interface Loopback0
ip address 2.2.2.2 255.255.255.0
!
interface Serial0/1
ip address 123.1.1.2 255.255.255.0
encapsulation frame-relay
frame-relay map ip 123.1.1.3 201 broadcast
frame-relay map ip 123.1.1.1 201 broadcast
frame-relay map ip 123.1.1.2 201 broadcast
no frame-relay inverse-arp
!
router eigrp 100
network 2.2.2.0 0.0.0.255
network 123.1.1.0 0.0.0.255
auto-summary
!
R3配置~
!
interface Loopback0
ip address 3.3.3.3 255.255.255.0
!
interface Serial0/2
ip address 123.1.1.3 255.255.255.0
encapsulation frame-relay
serial restart-delay 0
frame-relay map ip 123.1.1.3 301 broadcast
frame-relay map ip 123.1.1.1 301 broadcast
frame-relay map ip 123.1.1.2 301 broadcast
no frame-relay inverse-arp
!
router eigrp 100
network 3.3.3.0 0.0.0.255
network 123.1.1.0 0.0.0.255
auto-summary
!
!
问题在这里了:我的理解为,R2和R3都能通过EIGRP学习到对方的回环口的路由的,因为物理接口没有启用水平分割~
但是实验结果显示,只有R1学习到了R2、R3的回环口路由~
R2、R3只学习到了R1回环口(1.1.1.1)的路由~
R1路由表
1.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 1.1.1.0/24 is directly connected, Loopback0
D 1.0.0.0/8 is a summary, 00:33:24, Null0
D 2.0.0.0/8 [90/2297856] via 123.1.1.2, 00:24:50, Serial0/0
D 3.0.0.0/8 [90/2297856] via 123.1.1.3, 00:24:13, Serial0/0
123.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 123.1.1.0/24 is directly connected, Serial0/0
D 123.0.0.0/8 is a summary, 00:33:24, Null0
R2路由表
D 1.0.0.0/8 [90/2297856] via 123.1.1.1, 00:25:13, Serial0/1
2.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 2.2.2.0/24 is directly connected, Loopback0
D 2.0.0.0/8 is a summary, 00:29:40, Null0
123.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 123.1.1.0/24 is directly connected, Serial0/1
D 123.0.0.0/8 is a summary, 00:29:40, Null0
R3路由表
D 1.0.0.0/8 [90/2297856] via 123.1.1.1, 00:21:46, Serial0/2
3.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 3.3.3.0/24 is directly connected, Loopback0
D 3.0.0.0/8 is a summary, 00:16:10, Null0
123.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 123.1.1.0/24 is directly connected, Serial0/2
D 123.0.0.0/8 is a summary, 00:16:10, Null0
R1、R2、R3之间相互都能ping通(123.1.1.1/2/3)~
不知道这问题出在哪了?
还希望各位技术帝指点一下在下~!万分感谢!
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