晕倒~上面那么一大段,不去认真看,让我来推算~只好认了<br><br>首先,确认掩码为255.255.255.248(如果这不会的话,请重新学习NA课程相关内容,嘻嘻)<br>然后,若是ip subnet-zero,则从可用的子网依次为172.25.0.0,8.0,16.0,24.0……<br>若no ip subnet-zero,则零子网无效,172.25.0.0网段表示整个172.25B类网段,而不是170.25.0.子网,故而,本题第三个可用子网为172.25.24.0,第一个主机号为……<br><br>时间仓促,如果有错,请大家不要指出,谢谢合作!
Haha...Do you pay attention to the question that it ask you subnet the ip address accommodate FIVE Subnets,not FIVE Hosts each subnet?So,the netmark is 172.25.0.0/19,not 172.25.0.0/29.